![]() With anti - clockwise as + ve ΣM A = 0 wo (Δx)(Δx / 2) − T cosθΔy + T sin θΔx = 0ĥ.3 Cable Subjected to a Uniform Load Tmax θmax Consider this cable under distributed vertical load wo The cable force is not a constant.ĭ (T cos θ ) = 0 Eq 5.1 dx d (T sin θ ) = wo Eq 5.2 dx dy = tan θ Eq 5.3 dxįH Integrating Eq. 5.1 where T = FH at x = 0: ![]() Θ BA = 53.8 and TBA = 6.90kN Finally, h = (2m) tan 53.8o = 2.74mĤ Unknown external reactions (Ax, Ay, Dx and Dy) 3 Unknown cable tensions 1 Geometrical unknown h 8 Unknowns 8 Equilibrium conditions Cable is perfectly flexible & inextensible No resistance to shear/bending: same as truss bar The force acting on the cable is always tangent to the cable at points along its lengthĮxample 5.1 Determine the tension in each segment of the cable. Neglect cable weight Each segment is subjected to a constant tensile force Jordan University of Science & Technologyĭepartment of Civil Engineering Structural Analysis Professor Musa Resheidatĥ.2 Cable Subjected to Concentrated Loads
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